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| CHENMKO ENTERPRISE CO.,LTD SURFACE MOUNT NPN Digital Silicon Transistor VOLTAGE 50 Volts APPLICATION * Switching circuit, Inverter, Interface circuit, Driver circuit. CHDTC123JMPT CURRENT 100 mAmpere FEATURE * Small surface mounting type. (SOT-723) * High current gain. * Suitable for high packing density. * * * * Low colloector-emitter saturation. High saturation current capability. Internal isolated NPN transistors in one package. Built in bias resistor(R1=2.2k, Typ. ) 0.17~0.27 0.4 1.15~1.25 0.4 (1) SOT-723 (3) (2) 0.75~0.85 0.27~0.37 CONSTRUCTION * One NPN transistors and bias of thin-film resistors in one package. 0.17~0.27 0.75~0.85 0.11~0.14 0.45~0.55 Gnd In 1 CIRCUIT 2 1.15~1.25 R2 TR R1 3 Out Dimensions in millimeters SOT-723 LIMITING VALUES In accordance with the Absolute Maximum Rating System. SYMBOL VCC VIN IO DC Output current IC(Max.) PTOT TSTG TJ RJ-S Note 1. Transistor mounted on an FR4 printed-circuit board. 2004-06 PARAMETER Supply voltage Input voltage CONDITIONS - -5 - - Tamb 25 OC, Note 1 - MIN. MAX. 50 +12 100 V V UNIT mA 100 150 +150 150 140 mW O Total power dissipation Storage temperature Junction temperature Thermal resistance -55 - junction - soldering point - C C C/W O O RATING CHARACTERISTIC ( CHDTC123JMPT ) CHARACTERISTICS Tamb = 25 C unless otherwise specied. SYMBOL VIoff) VI(on) VO(on) II IC(off) hFE R1 R2/R1 fT PARAMETER Input off voltage Input on voltage Output voltage Input current Output current DC current gain Input resistor Resistor ratio Transition frequency IE=-5mA, VCE=10.0V f =100MHz CONDITIONS IO=100uA; VCC=5.0V IO=5mA; VO=0.3V IO=5mA; II=0.25mA VI=5V VI=0V; VCC=50V IO=10mA; VO=5.0V - - - - 80 1.54 17 - MIN. 0.5 - - 0.1 - - - 2.2 21 250 TYP. - 1.1 0.3 3.6 0.5 - 2.86 26 - K MHz MAX. V V V mA uA UNIT Note 1.Pulse test: tp300uS; 0.02. RATING CHARACTERISTIC CURVES ( CHDTC123JMPT ) Typical Electrical Characteristics Fig.1 Input voltage vs. output current (ON characteristics) 100 50 VO=0.3V Fig.2 Output current vs. input voltage (OFF characteristics) 10m 5m OUTPUT CURRENT : Io (A) VCC=5V INPUT VOLTAGE : VI(on) (V) 20 10 5 2 1 500m 200m 100m 100u 1m 2m 5m 10m 20m 50m 100m Ta =- 40OC 25OC = 100OC 2m 1m 500u 200u 100u 50u 20u 10u 5u 2u 1u 0 0.5 Ta=100OC 25OC -40 OC 1.0 1.5 2.0 2.5 3.0 OUTPUT CURRENT : IO (A) INPUT VOLTAGE : VI(off) (V) Fig.3 DC current gain vs. output current 1k 500 DC CURRENT GAIN : GI Fig.4 Output voltage vs. output current 1 500m OUTPUT VOLTAGE : VO(on) (V) VO =5V Ta=100OC 25OC -40OC lO/lI=20 200 100 50 20 10 5 2 1 100u 200m 100m 50m 20m 10m 5m 2m Ta=100OC 25OC -40 OC 1m 2m 5m 10m 20m 50m100m 1m 100u 1m 2m 5m 10m 20m 50m100m OUTPUT CURRENT : IO (A) OUTPUT CURRENT : IO (A) |
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