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  2008. 9. 11 1/2 semiconductor technical data KDS126U silicon epitaxial planar diode revision no : 1 ultra high speed switching application. features ? low forward voltage : v f =0.9v (typ.). ? fast reverse recovery time : t rr =1.6ns(typ.). ? small total capacitance : c t =0.9pf (typ.). maximum rating (ta=25 ? ) dim millimeters a b d g us6 2.00 0.20 1.25 0.1 2.1 0.1 0.2+0.10/-0.05 0-0.1 0.9 0.1 0.65 0.15+0.1/-0.05 b1 h c t g 1 3 2 b b1 d a h t 6 4 c c a1 1.3 0.1 a1 5 + _ + _ + _ + _ + _ 1. d1 anode 2. d2 anode 3. d3/d4 cathode 4. d3 anode 5. d4 anode 6. d1/d2 cathode electrical characteristics (ta=25 ? ) 123 6 5 4 marking ub type name lot no. characteristic symbol rating unit maximum (peak) reverse voltage v rm 85 v reverse voltage v r 80 v maximum (peak) forward current i fm 300 * ma average forward current i o 100 * ma surge current (10ms) i fsm 2 * a power dissipation p d 200 mw junction temperature t j 150 ? storage temperature range t stg -55 ?- 150 ? characteristic symbol test condition min. typ. max. unit forward voltage v f(1) i f =1ma - 0.60 - v v f(2) i f =10ma - 0.72 - v f(3) i f =100ma - 0.90 1.20 reverse current i r v r =80v - - 0.5 a total capacitance c t v r =0v, f=1mhz - 0.9 3.0 pf reverse recovery time t rr i f =10ma - 1.6 4.0 ns * this is maximum ratings of single diode (d1 or d2 or d3 or d4). in the case of using unit 1 and unit 2 independently or simultaneously, the maximum ratings per diode is 75% of the single diode one. 12 3 6 5 4 d1 d2 d4 d3 unit 2 unit 1 equivalent circuit (top view)
2008. 9. 11 2/2 KDS126U revision no : 1 1 0.1 reverse voltage v r (v) r t c - v reverse current i r ( a) 10 0 reverse voltage v r (v) total capacitance c t (pf) 0 i - v i - v forward voltage v f (v) 0 10 forward current i f (ma) f rr f 0.2 0.4 0.6 0.8 1.0 1.2 -2 -1 10 2 10 3 10 1 20 40 60 80 -3 -2 10 -1 10 1 10 0.4 0.8 1.2 1.6 2.0 31030100 t - i forward current i f (ma) 0.1 0.5 reverse recovery time t rr (ns) rr f 0.3 1 3 10 30 100 1 3 5 10 30 50 100 fig. 1. reverse recovery time (t rr ) test circuit 50 ? 2k ? e 50 ? input waveform input 0.01 f dut output sampling oscilloscope (r =50 ? ) in waveform 0.1 i r 0 f i =10ma rr t pulse generator (r =50 ? ) out 50ns -6v 0 10 f=1mhz fig. 1 ta=25 c ta=25 c i r 0.3 ta=100 c ta=25 c ta = -25 c ta=100 c ta=75 c ta=50 c ta=25 c


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